........... All about Solving Radical Equations..........

Hello Ma'am!!!!!!!!!
This is my blog on our lesson on solving radical equations..........

# How To solve radical expressions 1) Isolate radical on one side of the equation
# 2) Square both sides of the equation to eliminate radical
# 3) Simplify and solve as you would any equaitons
# 4) Substitute answers back into original equation to make sure that your solutions are valid (there could be some extraneous roots that do not satisfy the original equation and that you must throw out)

this lesson is very hard for me,,I cant understand this lesson very well................... hmmmmmmmmmmmmmmmmmmm!!!!!!!!!!!!!!!!!!

That's all for this week!!!!!!!!!!!!!!!!!!
GOD BLESS!!!!!!!!!!!!!!!!!!

........... All about on the division of Radicals...........

Hello Ma'am!!!!!!!!!
This is my blog on our lesson on the division of Radicals...............

This lesson is a little hard for me,,,,,,,,I can answer
on our discussion but,but when the test came,,,,,I
cant answer it anymore.......Haaaayyyyy........

The division of radical quantities may be expressed, by writing the divisor under the dividend, in the form of a fraction.

Thus the quotient of 3√a divided by √b, is 3√a/√b.

In this instance, the radical sign or index is separately applied to the numerator and the denominator. But if the divisor and dividend are reduced to the same index or radical sign, this may be applied to the whole quotient.

Thus n√a:n√b = n√a/b. For the root of a fraction is equal to the root of the numerator divided by the root of the denominator. (Art. 256.)

Again, n√ab:n√b = n√a. For the product of this quotient into the divisor is equal to the dividend, that is,
n√a.n√b = n√ab.

That's all for this week...........
GOD BLESS!!!!!!!!!!!!

.............All about Multiplication of Radicals...........

Hello Ma'am!!!!!!!!!!
This is my blog for our lesson in multiplication of radicals..............

Yeepee!!!! I've understand this lesson well,,,,
but.........but I don't know If I can answer
this equations if the tests come
But I'll try............

Radical quantities may be multiplied, like other quantities, by writing the factors one after another, either with or without the sign of multiplication between them. (Art. 91.)
Thus the product of √a into √b, is √a.√b.
The product of n1/3 into y1/2 is h1/3y1/2.

But it is often expedient to bring the factors under the same radical sign. This may be done, if they are first reduced to a common index.
Thus n√x.n√y = n√xy. For the root of the product of several factors is equal to the product of their roots.

That's all for this week............
GOD BLESS!!!!!!!!!!!!

...........All about on the ADDITION AND SUBTRACTION of Radicals..............

Hello Ma'am!!!!!!!!!!
This is my blog for the addition and subtraction of radicals.............

hhhhhhhhheeeeeeeeewwwwwwwww................. This lesson
is a little hard for me..........But I'm trying to
understand this very well so I can get a high
on our 4th periodical test and on the NAT...

4/5 + 3/7
Since the radicals are not the same, and both are in their simplest form, there is no way to combine them. The answer is the same as the problem.

Warning: If the radicals in your problem are different, be sure to check to see if the radicals can be simplified. Often times, when the radicals are simplified, they become the same radical and can then be added or subtracted. Always simplify, if possible, before deciding upon your answer

if the radical parts, after reduction, are different or have different exponents, they cannot be united in the same term; and must he added by writing them one after the other.
The sum of 3√b and 2√a, is 3√b + 2√a.

It is manifest that three times the root of b, and twice the root of a, are neither five times the root of b, nor five times the root of a, unless b and a are equal.
The sum of √a and 3√a, is √a + 3√a.

The square root of a, and the cube root of a, are neither twice the square root, nor twice the cube root of a.

272. Subtraction of radical quantities is to be performed in the same manner as addition, except that the signs in the subtrahend are to be changed according to Art. 81.
From √ay 3h1/3 -a-1/n
Sub. 3√ay -5h1/3 -2a-1/n
Diff. -2√ay 8h1/3 a-1/n

From √50, subtract √8. Ans. 5√2 - 2√2 = 3√2. (Art. 270.)
From 3√b4y subtract 3√by4. Ans. (b - y).3√x.
From n√x, subtract 5√x.

That's all for this lesson.............
GOD BLESS!!!!!!!!!!!!!!!